Bass: The bass in Clear Lake have weights that are normally distributed with a m

Question

Bass: The bass in Clear Lake have weights that are normally distributed with a mean of 2.1 pounds and a standard deviation of 0.9 pounds. (a) Suppose you only want to keep fish that are in the top 5% as far as weight is concerned. What is the minimum weight of a keeper? Round your answer to 2 decimal places. pounds (b) Suppose you want to mount a fish if it is in the top 0.5% of those in the lake. What is the minimum weight of a bass to be mounted? Round your answer to 2 decimal places. pounds (c) Determine the weights that delineate the middle 90% of the bass in Clear Lake. Round your answers to 2 decimal places. from to pounds

Explanation / Answer

Ans:

a)P(Z<z)=0.95

z=1.645

1.645=(x-2.1)/0.9

x=2.1+0.9*1.645=3.58

b)P(Z<z)=0.995

z=2.576

2.576=(x-2.1)/0.9

x=2.1+2.576*0.9=4.42

c)90% confidence interval

z value for 90 % confidence interval is 1.645

Confidence interval=2.1±1.645*0.9

=2.1±1.48

=(0.62,3.58)

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