A doctor wishes to determine whether the new drug Karmatum will produce beneific

Question

A doctor wishes to determine whether the new drug Karmatum will produce beneificial results in a higher proportion of patients suffering from stomachitis than the old drug Sicatum, for which the success rate is known to be 0.3 . To test this he gives Karmatum to 50 sufferers and finds 20 of them experience beneficial results.What should we conclude? I need the Ho,Ha,P-value,Z value, and whether there is evidence of the new drug being more successful.Could you please show all workings clearly.Thanks

Explanation / Answer

Sol:

Null Hpothesis

;Ho:p=0.3

Alternative hypothesis:

Ha:p>0.3

alpha=0.05

test statistc:

z=p^-p/sqrr[p(1-p)/n]

p^=sample proportion=x/n=20/50

z=0.4-0.3/sqrt[0.3(1-0.3)/50]

z=1.54

The P-Value is 0.06178.

The result is not significant at p < 0.05

Fail to reject Null hyppthesis as p<0.05

Accept null hypothesis

There is no sufficent evidence at 5% level of significance to support the claim.

conclusion:

there is no evidence of the new drug being more successful

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