A researcher wanted to determine whether pedestrian deaths were uniformly distri
ID: 3236961 • Letter: A
Question
A researcher wanted to determine whether pedestrian deaths were uniformly distributed over the days of the week. She randomly selected 300 pedestrian deaths, recorded the day of the week on which the death occurred, and obtained the following results.
Sunday
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
43
40
34
45
39
44
55
Test the belief that the day of the week on which a fatality happens involving a pedestrian occurs with equal frequency at the a(Symbol) = .01
Sunday
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
43
40
34
45
39
44
55
Explanation / Answer
2 = 5.946666667
p- value = 0.429191021
Since 0.43 > 0.01, we fail to reject the null hypothesis is uniform distribution.
Conclusion: There is no sufficient evidence that the distribution is different from a uniform distribution.
Recorded Expected (Recorded - Expected)^2 / Expected 43 42.85714286 0.00047619 40 42.85714286 0.19047619 34 42.85714286 1.83047619 45 42.85714286 0.107142857 39 42.85714286 0.347142857 44 42.85714286 0.03047619 55 42.85714286 3.44047619 2 = 5.946666667Related Questions
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