The contingency table below from a survey of 200 randomly selected Macomb County
ID: 3232968 • Letter: T
Question
The contingency table below from a survey of 200 randomly selected Macomb County registered voters. This survey was conducted to test the claim that vectors opinions on a particular bill are independent of their party affiliation. At alpha = 0.05, what is the critical value? 13.277 11.143 7.779 9.488 None of these Find the expected frequency (E) used in the calculation of the xi^2 test statistic for the cell in the third row (Independent) and second column (Disapprove). (This is the cell that has an observed value of O = 16) 9.6 17.48 16.32 16 None of these Given that the rank correlation coefficient for 27 pairs of data is r_s = 0.412, test the claim of no correlation between the two variables. Use a significance level of 0.01 Critical Values r_s = plusminus 0.448; There does not appear to be a correlation between the variables. Critical values r_s = plusminus 0.448; There appears to be a correlation between the variables. Critical Values r_s = plusminus 0.501; There does not appear to be a correlation between the variables. Critical values r_s = plusminus 0.491: There does not appear to be a correlation between the variables. Critical Values r_s = plusminus 0.491; There appears to be a correlation between the variables.Explanation / Answer
83) From chi square table the value of chisquare at 0.05 level with(3-1)(3-1) = 4 df is 9.488 option d) correct
84) the expected frequency of 3rd row 2nd column is (32)60)/200= 9.6 option a) correct
85) option c) is correct i.e there does not apper to be a correlation between the variables
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