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Suppose that the sales manager of a large automotive parts distributor wants to

ID: 3232369 • Letter: S

Question

Suppose that the sales manager of a large automotive parts distributor wants to estimate as early as April the total annual sales.

According to the manager of the distribution warehouse, several factors are related to annual sales (measured in millions of dollars) (sales), including the number of retail outlets in the region stocking the company’s parts (outlets), the number of automobiles in the region registered as of April 1 (measured in millions) (cars), the total personal income for the first quarter of the year (measured in billions of dollars) (income), the average age of automobiles in years (age), and the number of supervisors at the distribution warehouse (bosses). The data for all these variables were gathered for a recent year.

                                                      

Consider the following correlation matrix.

sales

outlets

cars

income

age

outlets

0.899

cars

0.605

0.775

income

0.964

0.825

0.409

age

-0.323

-0.489

-0.447

-0.349

bosses

0.286

0.183

0.395

0.155

0.291

A. Which single variable has the strongest correlation with the dependent variable? Is there evidence of multicollinearity? If so, between what variables?

Using the data, the following multivariate regression equation was estimated:

sales = -19.7 – 0.00063 outlets – 1.74 cars + 0.410 income + 2.04 age – 0.034 bosses

The output for all five variables is shown below.

Predictor

Coef

SE Coef

T

P

Constant

-19.672

5.422

-3.63

0.022

Outlets

-0.000629

0.002638

-0.24

0.823

Cars

-1.7399

0.5530

3.15

0.035

Income

0.40994

0.04385

9.35

0.001

Age

2.0357

0.8779

2.32

0.081

bosses

-0.0344

0.1880

-0.18

0.864

Analysis of Variance

SOURCE

DF

SS

MS

F

P

Regression

5

1593.81

318.76

140.36

0.000

Residual Error

4

9.08

2.27

Total

9

1602.89

B. State the null hypothesis concerning the statistical significance of the overall regression, test this hypothesis, and interpret the results. (use a .05 level of significance)

C. What percent of the variation is explained by the regression equation?

D. Interpret the results (both statistical significance and magnitude of effect) for each of the independent variables in the model. (Use a .05 level of significance)

E. What would be the projected value in annual sales if the following were true?
outlets = 1739, cars = 9.27, income = 85.4, age = 3.5, and bosses = 9.0
If these values are outside the range of values used for the regression, would this be a reliable forecast? Why or why not?

sales

outlets

cars

income

age

outlets

0.899

cars

0.605

0.775

income

0.964

0.825

0.409

age

-0.323

-0.489

-0.447

-0.349

bosses

0.286

0.183

0.395

0.155

0.291

Explanation / Answer

A.

Income has the strongest correlation with the dependent variable i.e. sales. Cars and outlets and income and outlets are highly correlated amongst themselves. Hence, these variables suggest multicollinearity.

B.

H0: 1 = 2 = 3 = 4 = 5 = 0 (no linear relationship)

H1: at least one i 0   (at least one independent variable affects Y)

FSTAT is 140.36 and FCRIT is 6.256 and Hence FSTAT > FCRIT and lies in the rejection region and hence reject null hypothesis. This proves that at least one independent variable affects Y.

C.

r^2=SSR/SST=1593.81/1602.89=0.9943 or 99.43%

D.

Outlets:- p-value= 0.823, not significant, For every increase of 1 in outlets, sales would go down by 0.000629.

Cars:- p-value= 0.035, significant, For every increase of 1 in cars, sales would go down by 1.7399.

Income:- p-value= 0.001, significant, For every increase of 1 in income, sales would go up by 0.40994.

Age:- p-value= 0.081, not significant, For every increase of 1 in age, sales would go up by 2.0357.

Bosses:- p-value= 0.864, not significant, For every increase of 1 in bosses, sales would go down by 0.0344.

E.

Sales = -19.7 – 0.00063 outlets – 1.74 cars + 0.410 income + 2.04 age – 0.034 bosses

= -19.7-0.00063(1739)-17.4(9.27)+0.0410(85.4)+2.04(3.5)-0.034(9)

= -19.7-1.09557-161.28+3.5014+7.14-0.306

= -171.75817

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