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During my kids opening day for baseball, there are a series of raffle prizes. Du

ID: 3230919 • Letter: D

Question

During my kids opening day for baseball, there are a series of raffle prizes. During the course of the day there are 10 different prizes that people can place raffle tickets in a basket for. At the end of the day, a single ticket is pulled from the tickets submitted for each prize. For this problem at the end of the day each basket of tickers has 200 tickets in it. My daughter has 10 tickets. She wants to at least one prize. She wants to know if it is better put all 10 tickets in 1 basket or put 1 ticket in each of the 10 baskets. To determine the probability that at least one of the events will occur, examine the probability that none of the events will occur. Please provide calculations and an answer to which is better-all in basket or 1 in each.

Explanation / Answer

case 1: all ticket in one basket:

probabilty of winning =10/200 =0.05 (as there are 10 facourable chance out of 200)

case 2: each basket has one ticket

probabilty of winning at lest one prize=1-P(of winning nothing)=1-(199/200)10 =1-0.95111=0.04889

as probability in case 1 is higher of winning ; all in 1 basket strategy is better

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