Let the paired difference be the number of crimes before minus the number of cri

Question

Let the paired difference be the number of crimes before minus the number of crimes after the city launched the neighborhood watch program. The null hypothesis is that the mean of the population paired differences is equal to zero (i.e. the neighborhood watch program does not affect the number of crimes.) The alternative hypothesis is that the mean of the population paired differences is different than zero (i.e., the neighborhood watch program decreases the number of crimes). The significance level is 1%.before numbers are 57,73,53,82,79,39,after numbers are,41,65,28,73,61,32

What is the standard deviation of the paired differences?

A. 7.083

B. 33.88

C. 22.571

D. 5.821
What is the value of the test statistic, t

A. 3.67

B. 11.72

C. 4.78

D. 9.77What is the mean of the sample paired differences?

A. 13.83

B. 16.60

C. 68.30

D. 11.86

Explanation / Answer

from above :

standard deviation of the paired differences 7.083 option A

value of the test statistic, t =4.78 option C

mean of the sample paired differences =13.83 option A

before after difference(d) 57 41 16 73 65 8 53 28 25 82 73 9 79 61 18 39 32 7 mean 13.833 std deviaition 7.0828 sample size 6.0000 std error= std dev/(n)^(1/2) 2.8916 t stat= (d)/std error 4.7840

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