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Customers experiencing technical difficulty with their Internet cable hookup may

ID: 3229892 • Letter: C

Question

Customers experiencing technical difficulty with their Internet cable hookup may call an 800 number for technical support. It takes the technician between 30 seconds to 12 minutes to resolve the problem. The distribution of this support time follows the uniform distribution.

  

What are the values for a and b in minutes? (Round your intermediate & final answers to 2 decimal places.)

   

    

What is the mean time to resolve the problem? (Round your intermediate & final answer to 2 decimal places.)

   

    

What is the standard deviation of the time? (Round your intermediate & final answer to 2 decimal places.)

   

    

What percent of the problems take more than 5 minutes to resolve? (Round your intermediate & final answer to 2 decimal places.)

   

     

Suppose we wish to find the middle 50% of the problem-solving times. What are the end points of these two times? (Round your intermediate values to 2 decimal places & final answers to 3 decimal places.)

    

rev: 07_21_2014_QC_51144

Customers experiencing technical difficulty with their Internet cable hookup may call an 800 number for technical support. It takes the technician between 30 seconds to 12 minutes to resolve the problem. The distribution of this support time follows the uniform distribution.

Explanation / Answer

(a)
Values of a and b0.608695652

a = 30 sec
b = 720 sec

(b)
Mean = 1/2*(a+b) = 375 sec

(c)
variance = 1/12(b-a)^2 = 39675
std. dev. = sqrt(variance) = 199.19

(d)
Here we need to find the percent of problems which takes more than 300 sec

Required probability = (b - x)/(b - a) = (720 - 300)/(720 - 30) = 0.6087

Hence 60.87% of porblems take more than 5 minutes to resolve.

(e)
Let x1 and x2 be the lower and upper end points.

0.25 = (720 - x2)/(720 - 30)
x2 = 547.5

0.75 = (720 - x1)/(720 - 30)
x1 = 202.5

End point 1 = 202.5 sec
End point 2 = 547.5 sec

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