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A genetic experiment involving peas yielded one sample of offspring consisting o

ID: 3228794 • Letter: A

Question

A genetic experiment involving peas yielded one sample of offspring consisting of
419
green peas and
147
yellow peas. Use a
0.01
significance level to test the claim that under the same circumstances,
27
%
of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.

Explanation / Answer

Null hypothesis H0: p=0.27

Alternative hypothesis Ha:p0.27

Phat=147/(147+419)=0.2597

Sample size n=147+419=566

Test statistic Z=(phat-0.27)/sqrt(0.27*(1-0.27)/n)

=(0.2597-0.27)/sqrt(0.27*(1-0.27)/566)

=-0.5520

p-value (Two tailed)=0.581 using excel =2*NORMSDIST(-0.552)

As p-value is greater than even 10% level of significance we do not reject the null hypothesis and conclude that under the same circumstances, 27% of offspring peas will be yellow.

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