We would like to assess whether mothers in San Lorenzo have the same knowledge o

Question

We would like to assess whether mothers in San Lorenzo have the same knowledge of the emergency plan to take care of their sick children compared with mothers in Comitancillo . Develop a contingency table and calculate the Chi-squared statistic comparing the variables municipal and emergency.

Below you will find some questions. Give a one sentence answer below each question.

Questions

1. What would the null hypothesis be for this comparison?

2. What number and proportion of mothers in San Lorenzo reported knowing the emergency plan?

3. What number and proportion of mothers in Comitancillo reported knowing the emergency plan?

4. What is the derived Chi-square statistic and significance value?

5. What are your conclusions based on this analysis?

Case Processing Summary

Cases

Valid

Missing

Total

N

Percent

N

Percent

N

Percent

MUNICIPAL:municipality * EMERGENCY:mother knows the emergency plan for seeking help for sick children

1604

99.9%

1

0.1%

1605

100.0%

MUNICIPAL:municipality * EMERGENCY:mother knows the emergency plan for seeking help for sick children Crosstabulation

EMERGENCY:mother knows the emergency plan for seeking help for sick children

Total

no

yes

MUNICIPAL:municipality

san lorenzo

Count

120

282

402

% within MUNICIPAL:municipality

29.9%

70.1%

100.0%

% within EMERGENCY:mother knows the emergency plan for seeking help for sick children

18.2%

29.8%

25.1%

comitancillo

Count

538

664

1202

% within MUNICIPAL:municipality

44.8%

55.2%

100.0%

% within EMERGENCY:mother knows the emergency plan for seeking help for sick children

81.8%

70.2%

74.9%

Total

Count

658

946

1604

% within MUNICIPAL:municipality

41.0%

59.0%

100.0%

% within EMERGENCY:mother knows the emergency plan for seeking help for sick children

100.0%

100.0%

100.0%

Chi-Square Tests

Value

df

Asymptotic Significance (2-sided)

Exact Sig. (2-sided)

Exact Sig. (1-sided)

Pearson Chi-Square

27.673a

1

.000

Continuity Correctionb

27.060

1

.000

Likelihood Ratio

28.417

1

.000

Fisher's Exact Test

.000

.000

Linear-by-Linear Association

27.656

1

.000

N of Valid Cases

1604

a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 164.91.

b. Computed only for a 2x2 table

Questions

1. What would the null hypothesis be for this comparison?

2. What number and proportion of mothers in San Lorenzo reported knowing the emergency plan?

3. What number and proportion of mothers in Comitancillo reported knowing the emergency plan?

4. What is the derived Chi-square statistic and significance value?

5. What are your conclusions based on this analysis?

Explanation / Answer

1. What would the null hypothesis be for this comparison?

mothers in San Lorenzo have the same knowledge of the emergency plan to take care of their sick children compared with mothers in Comitancillo

2. What number and proportion of mothers in San Lorenzo reported knowing the emergency plan?

282, 29.8%

3. What number and proportion of mothers in Comitancillo reported knowing the emergency plan?

664, 70.2%

4. What is the derived Chi-square statistic and significance value?

27.673, 3.8414(for 5% level of significance)

5. What are your conclusions based on this analysis?

Reject H0 and conclude that mothers in San Lorenzo does not have the same knowledge of the emergency plan to take care of their sick children compared with mothers in Comitancillo

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