From Table 1 (below): a. Calculate the probability of each 9 THC %. b. What is t

Question

From Table 1 (below):

a. Calculate the probability of each    9 THC %.

b. What is the probability that the   9 THC content of marijuana from 2006 is equal to or less than 8%? Show your calculations.

c. What percentage of marijuana seizures from 2006 has a   9 THC content between 7% and 8.5%? Show your calculations.

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d. If the THC content of a seizure from an unknown year is 7.5%, would it be true to say that there is a 50% probability it came from 2006? Explain your response.

9THC %      Seizure count Probability 6.0-6.5

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? 6.5-7.0 0 ? 7.0-7.5 2 ? 7.5-8.0 2 ? 8.0-8.5 6 ? 8.5-9.0 3 ? 9.0-9.5 2 ? 9.5-10 2 ? 10-10.5 1 ? 10.5-11 1 ?

Explanation / Answer

(A)

(B)

P(X<8) = 0.05 + 0 + 0.1 + 0.1 = 0.25

(C)

P(7<X<8.5) = 0.1 + 0.1 + 0.3 = 0.5

9THC %      Frequency (f) Midpoint (m) f*m Probability (f/total) 6.0-6.5 1 6.25 6.25 0.05 6.5-7.0 0 6.75 0 0 7.0-7.5 2 7.25 14.5 0.1 7.5-8.0 2 7.75 15.5 0.1 8.0-8.5 6 8.25 49.5 0.3 8.5-9.0 3 8.75 26.25 0.15 9.0-9.5 2 9.25 18.5 0.1 9.5-10 2 9.75 19.5 0.1 10-10.5 1 10.25 10.25 0.05 10.5-11 1 10.75 10.75 0.05 Total 20

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