Data Presentation and Interpretation: Choose one of the research scenarios in th
ID: 3224441 • Letter: D
Question
Data Presentation and Interpretation: Choose one of the research scenarios in the attachment below and respond to the prompt.
4a. Chi-Square Goodness of Fit: A researcher wanted to evaluate preferences for cars between Ford and Chevy. Review the data below and present your interpretation of the data in APA format. Explain how you arrived at your answer.
Descriptive Statistics
N
Mean
Std. Deviation
Minimum
Maximum
Preference
35
1.4571
.50543
1.00
2.00
Preference
Observed N
Expected N
Residual
Ford
19
17.5
1.5
Chevrolet
16
17.5
-1.5
Total
35
Test Statistics
Preference
Chi-Square (a)
.257
df
1
Asymp. Sig.
.612
a. 0 cells (0%) have expected frequencies less than 5. The minimum expected cell frequency is 17.5.
4b. Chi-Square Test for Independence: A researcher wanted to test whether the preference for Coke, Pepsi, or Sprite depended on gender (male or female). Review the data below and present your interpretation of the data in APA format. Explain how you arrived at your answer.
Case Processing Summary
Cases
Valid
Missing
Total
N
Percent
N
Percent
N
Percent
prefer*gender
152
100.0%
0
0%
152
100.0%
prefer * gender Crosstabulation
gender
Total Females
Females
Males
prefer
Coke
Count
21
33
54
% within prefer
38.9%
61.1%
100.0%
% within gender
23.3%
53.2%
35.5%
Pepsi
Count
42
17
59
% within prefer
71.2%
28.8%
100.0%
% within gender
46.7%
27.4%
38.8%
Sprite
Count
27
12
39
% within prefer
69.2%
30.8%
100.0%
% within gender
30.0%
19.4%
25.7%
Total
Count
90
62
152
% within prefer
59.2%
40.8%
100.0%
% within gender
100.0%
100.0%
100.0%
Chi-Square Tests
Value
df
Asymp. Sig. (2-sided)
Pearson Chi-Square
14.358(a)
2
.001
Likelihood Ratio
14.358
2
.001
Linear-by-Linear Association
9.953
1
.002
N of Valid Cases
152
a. Zero cells (0%) have expected count less than 5. The minimum expected count is 15.91.
Cramer’s V
Formula
Value
2/ N x dfsmaller
Cramer’s V
14.358 / 152 x 1 = .094
.307
N of Valid Cases
152
N
Mean
Std. Deviation
Minimum
Maximum
Preference
35
1.4571
.50543
1.00
2.00
Explanation / Answer
Question-4a
The assumption of chi-square test of goodness of fit are satisfied as expected count are all greater than 5. The results of chi-square test were not significant at even 10% level of significance ,2(1)=0.26, p=0.612. Hence, there is equal preference of Ford and Chevy cars amongst customers.
Question-4b
The assumption of chi-square test of goodness of fit are satisfied as expected count are all greater than 5. The results of chi-square test were significant at 0.1% level of significance ,2(2)=14.36, p=0.001. Hence, preference for coke , pepsi or Sprite depends on gender.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.