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Question 2.3. (GET FLU SHOT ON TIME) Suppose A be the event that the first child

ID: 3223291 • Letter: Q

Question

Question 2.3. (GET FLU SHOT ON TIME) Suppose A be the event that the first child has influenza and B be the event that the second child has influenza. Further assume that both the events A and B are independent. The probability that neither of the DGC children have influenza is 0.75 DGC 5000 and the probability that the second child has influenza is 0.15. What is the probability that the first child has influenza? Question 2.4 (PLACEBOEFFECT) A nurse is to administer six flu injections to six patients. Three of the injections are in fact placebos. How many choices are there of the three patients to receive the placebos.

Explanation / Answer

First question is 2.4

Rest all are different questions.

So, I will answer only this question 2.4.

Given, P((not A) and (not B)) = P(none have influenza) = 0.75 + (DGC/ (DGC/5000) ) = 0.75596

also given: P(B) = 0.15

To compute: P(A)

Now, P(not B) = 1- P(B) = 1-0.15 = 0.85

and since A and B are independent, the events (not A) and (not B) are also independent.

So, P((not A) and (not B)) = P(not A) * P(not B) = P(not A) * 0.85 = 0.75596

So, P(not A) = 0.75596 / 0.85

So, P(A) = 1 - P(not A) = 1 - 0.75596/0.85 = 0.110635294 = 0.111

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