1. You are testing the null hypothesis p = 0.4 and will reject this hypothesis i

Question

1. You are testing the null hypothesis p = 0.4 and will reject this hypothesis if z is less than -2.03. (Give your answers correct to four decimal places.)

(b) What is the significance level for this test?


(c) What is the p-value for z = -2.18?

2. Find the values of t that bound the middle 0.99 of the distribution for df = 22. (Give your answers correct to two decimal places.)
to  

3. Construct a 98% confidence interval estimate for the mean using the given sample information. (Give your answers correct to two decimal places.)

n = 22, x = 16.5, and s = 2.7

Explanation / Answer

Q-1:

Part-b

Significance level is 2% as for 2% level left tailed critical z=-2.03

Part-c

p-value=P(Z<-2.18)=0.0146

Q-2: The bounds are -2.82 and 2.82 using excel fucntion =tinv(0.01,22)

Q-3

Degree of freedom =n-1=22-1=21

Critical t=2.52 using excel function =TINV(0.02,21)

So, 98% confidence interval=xbar-2.52*s/sqrt(n) , xbar+2.52*s/sqrt(n)

=16.5-2.52*2.7/sqrt(22) , 16.5+2.52*2.7/sqrt(22)

=(15.05 , 17.95)

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