nesum: that asimple random sample has been selcct-d from a normally stributed po

Question

nesum: that asimple random sample has been selcct-d from a normally stributed population and test tho gren lam. Identity the null and a hernative hypothc 1est etatiebc. P. value, and statc tho final that addre the original claim. A Rimni gth at 7188 sample is from population of songs with reater th 210 What agost about the advic displ Wha: the hypotheses? A. Hh H, u 210 ses O D. How 210 How H, u 210 sec H u 210 sec t- IRound to two decimal pl as needed.) Identify the P The P-walucis Round to th decimal Flacesas needed A. He actHn. hare suthciant encence to support thi clam that he sampla s trnm a Populahan otr songs with a maan langth greater than 210 a: C B. Falto reject Hb increis sutticent andenca 1 supportne claim that the sample trom a population otsong wrth a mean length greater than 21 uscc. C c. Reject Ilo. There is insuttcient cidence to support caim that the sample is from a populat ngs with a mcan gth greator than 210 sec. C D. Fail reject l There isin cwidenco to support th clam that the sample is To a population of songs with a moan length grcater than 210 sufficient What do sults suggest about the acvi ot wmting a song that must ba longer tha R. The O C. The D. Thor do not suggost that the adica of st be 210 panying Mini tain display tastthA

Explanation / Answer

Hypothesis;

Ho : mu = 210 sec
H1 : mu > 210 sec

test statistic:
x = 218.8 , s = 55.92 , n = 40

t = ( x - mean) / ( s/ sqrt(n))
= ( 218.8 - 210) / ( 55.92 / sqrt(40))
= 0.995

now, we need to find p value using t = 0.995 , df = 39
p value = .162935.

Fail to reject H0. There is insufficient evidence to support the claim that the sample is from population of songs with a mean length greater than 210 sec
Answer is Option D)

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