The followings are the questions I have trouble to answer. I am appreciated your
ID: 3222173 • Letter: T
Question
The followings are the questions I have trouble to answer. I am appreciated your help. May I ask if you provide a step by step explanation, please? Thanks!
1.
A survey claims that 8 out of 10 doctors recommend aspirin for their
patients with headaches. Let p the population proportion of doctors
who recommend aspirin for their patients with headaches. To test
H0 : p = 0.8 vs. Ha : p 6= 0.8, a random sample of 100 doctors’
results in 86 who indicate that they recommend aspirin. Based on the
data set, find the Pvalue of the test.
(a) Pvalue 0.1151
(b) Pvalue 0.2302
(c) Pvalue 0.1336
(d) Pvalue 0.0668
2.
Independent random samples, each containing 800 observations, were
selected from two populations. The samples from populations I and II
produced 320 and 400 successes, respectively. Let p 1 and p 2 denote,
respectively, the true proportions of successes of populations I and II.
Find the pooled estimator for q when q1 = q2 where q1 = 1 p 1 and
q2 = 1 p 2.
(a) 0.55
(b) 0.10
(c) 0.60
(d) 0.60
3.
A sample of size 400 selected from first population has 250 successes,
and a sample of size 200 selected from second population has 150
successes. You are asked to use pooled method for testing the equality
of the two population proportions. Find the observed value of your test
statistic.
(a) 3.2026
(b) 3.0619
(c) 2.8868
(d) 6.4952
Explanation / Answer
Question-1
Sample proportion phat=86/100=0.86
Z-statistic =(phat-0.8)/sqrt(0.8*(1-0.8)/n)
=(0.86-0.8)/ sqrt(0.8*(1-0.8)/100)
=1.5
Two tailed p-value=2*P(Z<-1.5)=2*0.0668=0.1336
So, part-c is answer
Question-2
Pooled estimator of p=(x1+x2)/(n1+n2) = (320+400)/(800+800) =0.45
So, pooled estimator of q=1-0.45=0.55
So part-a is answer
Question-3
Pooled estimator of p=(x1+x2)/(n1+n2) = (250+150)/(400+200) =0.6667
Phat1=250/400=0.625
Phat2=150/200=0.75
Test statistic z= (phat1-phat2)/sqrt(p*(1-p)/(1/n1+1/n2))
=(0.625-0.75)/sqrt(0.6667*(1-0.6667)*(1/400+1/200))
=-3.0619
So, option-b is answer
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