Listed below are the amounts of mercury (in parts per million, or ppm) found in

ID: 3221490 • Letter: L

Question

Listed below are the amounts of mercury (in parts per million, or ppm) found in tuna sushi sampled at different stores. The sample mean is

1.3231.323

ppm and the sample standard deviation is

0.1470.147

ppm. Use technology to construct a

9090%

confidence interval estimate of the mean amount of mercury in the population.

1.351.35

1.341.34

1.331.33

1.261.26

1.041.04

1.491.49

1.451.45

What is the confidence interval estimate of the mean amount of mercury in the population?

nothing

ppmless than<muless than<nothing

ppm

(Round to three decimal places as needed.)

1.351.35

1.341.34

1.331.33

1.261.26

1.041.04

1.491.49

1.451.45

here sample size is not given, please look once again the question and find sample size n.

(1-alpha)*100% confidence interval for population mean=sample mean± z(alpha/2)*sd/sqrt(n)

here alpha=0.1 or (1-0.1) confidence

90% confidence interval for mean=mean±z(0.1/2)*sd/sqrt(n)=1.323±1.645*0.147/sqrt(n)

=1.323±0.242/sqrt(n)=(1.323-0.242/sqrt(n), 1.323+0.242/sqrt(n))

please put the sample size and you will get the confidence interval.

if sample size=36, then

90% confidence interval =(1.323-0.242/sqrt(36), 1.323+0.242/sqrt(36))=(1.283, 1.363)

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.