Ronin is a Human Resources Manager Burgerville. He wants to add a personality te

Question

Ronin is a Human Resources Manager Burgerville. He wants to add a personality test to the selection took for cashiers under the assumption that more agreeable employees have significantly (a = .05) more satisfied customers. Before adding an agreeableness survey to the selection tools, he administers the following agreeableness survey to current employees. I see myself as someone who is considerate and kind to almost anyone. (completely disagree). (stronly disagree), (disagree), (neither agree nor disagree) (agree) (strongly agree) (completely agree) is sometimes rude to others. H (completely degree) (strongly agree) (agree) (neither agree nor disagree) (disagree) (strongly disagree) (completely agree) can be cold and aloof. 0 (completely disagree) (strongly agree) (agree) (neigher agree nor disagree) (disagree) (strongly disagree) (completely agree) He also administers the following customer satisfaction survey to customers for 2 weeks. My cashier was friendly today. 0 (completely disagree) (strongly disagree) (disagree) (neither agree nor disagree) (agree) (strongly agree) (completely agree) My cashier helped me have a pleasant dining experience today. 0 (completely disagree) (strongly disagree) (disagree) (neither agree) My cashier's name ws ____ What is the critical value of the data below (X = mean agreebleness and Y = mean customer satisfaction)? r crit = .805 r crit = .878 r cri = .669 r crite = .754

Explanation / Answer

for above degree of freedom =n-2=3

here for 0.05 level and 3 degree of freedom t=3.1824

and as we know that t=r((n-2)/(1-r2))1/2

hence r critical =0.878

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