Ronin is a Human Resources Manager at Burgerville. He wants to add a personality

Question

Ronin is a Human Resources Manager at Burgerville. He wants to add a personality test to the selection tools for cashiers under the assumption that more agreeable employees will have significantly (a = .05) more satisfied customers. Before adding agreeableness survey to the selection tools, he administers the following an agreeableness survey to current employees. I see myself as someone who. 1. is considerate and kind to almost anyone. 0 (completely disagree). 1 (strongly disagree), 2 (disagree), 3 (neither agree nor disagree), 4 (agree), 5 (strongly agree), 6 (completely agree) 2. sometimes rude to others. 0 (completely disagree) 1 (strongly agree), 2 (agree), 3 (neither agree nor disagree), 4 (disagree), 5strongly disagree), 6 (completely agree) 3. can be cold and aloof. 0 (completely disagree), 1 (strongly agree), 2 (agree), 3 (neither agree nor disagree), 4 (disagree), 5 (strongly disagree) 6 (completely agree) He also administers the following customer satisfaction survey to customers for 2 weeks. 1. My cashier was friendly today, 0 (completely disagree) 1 (strongly disagree), 2 (disagree), 3 (neither agree nor disagree), 4 (agree), 5 (strongly agree), 6 (completely agree) 2. My cashier helped me have a pleasant dining experience today, 0 (completely disagree), 1 (strongly disagree), 2 (disagree), 3 (neither agree nor disagree), 4 (agree), 5 (strongly agree), 6 (completely agree) 3. My cashier's name was _______ What is the critical value for the data below (X = mean agreeableness and Y = mean customer satisfaction)? r crit = .805 r crit = .978 r crit = .669 r crit = .754

Explanation / Answer

here for we need to check for +ve correlatiion from above data and for degree of freedom =(n-2)=3

hence r critical =0.805

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