A pair of eight-sided dice has sides numbered 1 through 8. Each side has the sam

Question

A pair of eight-sided dice has sides numbered 1 through 8. Each side has the same of landing face up. What is the probability that the product of the two numbers on the sides face up exceeds 36? A sales representative for a tire manufacturer claims that the company's steel-belted at least 35,000 miles. A tire dealer decided to check that claim by testing eight of the or more of the eight tires he tests last at least 35,000 miles, he will purchase tires representative. If, in fact, 90 % of the steel-belted radials produced by the manufacture least 35,000 miles, what is the probability that the tire dealer will purchase tires from representative?

Explanation / Answer

1. Pairof 8 sided dice rolled so total number of outcomes possible = 8*8 = 64

Pairs in which the product is greater than 36: (6, 7), (6, 8), (7, 6), (7, 7), (7, 8), (8, 6), (8, 7), (8, 8)

So total number of such pairs = 8

Hence,

P(Product exceeds 36)

= 8/64

= 1/8

= 0.125

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