A genetics experiment involves a population of fruit flies consisting of 1 male

Question

A genetics experiment involves a population of fruit flies consisting of 1 male and 3 females. Assume that two fruit flies are randomly selected with replacement.

a. After listing the possible samples and finding the proportion of malesmales in each sample, use a table to describe the sampling distribution of the proportion of malesmales. Proportion of malesmales Probability 0 nothing 0.5 nothing 1 nothing

Proportion of males

Probability

0

nothing

0.5

nothing

1

nothing

b. Find the mean of the sampling distribution.

=?

Proportion of males

Probability

0

nothing

0.5

nothing

1

nothing

Explanation / Answer

a.Here we have 1 male and 3 females

Let us put 1 for male and b,c and d for females

So total number of paris with replacement will be 4^2=16

So we have sample as {(a,a),(a,b),(b,a),(a,c),(c,a),(a,d),(d,a),(b,c),(c,b),(b,d),(d,b),(b,b),(c,c),(d,d),(c,d),(d,c)}

Proportion are as below

0 males=9/16

1 male=6/16

2 males=1/16

b. Now mean=Sum(xP(x)= (9/16)*0+(6/16)*1+(1/16)*2 = 8/16 = 1/2

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