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Unethical Behavior of Business Students at Bayview University During the global

ID: 3217575 • Letter: U

Question

Unethical Behavior of Business Students at Bayview University

During the global recession of 2008 and 2009, there were many accusations of unethical behavior by Wall Street executives, financial managers, and other corporate officers. An article appeared at that time, suggesting that part of the reason for such unethical business behavior may stem from the fact that cheating has become more prevalent among business students (Chronicle of Higher Education, February 10, 2009). The article reported that 56% of business students admitted to cheating at some time during their academic career as compared to 47% of nonbusiness students.

The dean of the College of Business at Bayview and many professors have assumptions about their students regarding cheating behavior. Some think it is a major problem; others do not. To resolve some of these issues, you decide to use a class capstone project to conduct a study about cheating behavior at Bayview. As part of your study, you decide to administer an anonymous exit survey to 90 business students from this year's graduating class. Responses to the following questions will be used to obtain data about three types of cheating.

     During your time at Bayview, did you ever present work copied from the Internet as your own? Yes / No.

     During your time at Bayview, did you ever copy answers from another student's exam? Yes/No.

     During your time at Bayview, did you ever collaborate with other students on projects that were supposed to be completed individually? Yes/No.

Any student who answers Yes to one or more of these questions will be considered to have been involved in some type of cheating.

An important part of your study is to determine if Bayview's proportion of cheating students, p-bar = 0.4111, is significantly less (in the statistical sense) than the article's proportion, p0 = 0.56. While lower, the sample proportion could be within the range of what you would expect due to random variation in samples taken from a population where p = 0.56.

1) What would the p-value have been if only 35 students had responded to your survey? What decision would you have made about your hypothesis test in that situation? Assume the same sample proportion, p-bar = 0.4111.

A) 0.0022, Fail to Reject H0

B) 0.0576, Reject H0

C) 0.0668, Fail to Reject H0

D) 0.038, Reject H0

2) After calculating the proportion of Bayview students who have cheated to be p-bar = 0.4111, you would like to place the sampling distribution of p-bar and its 95% confidence interval in your research report. Which distribution below would be the correct one to use? (I made links to the graphs since they are huge)

A) http://i.imgur.com/oLO40Lj.jpg

B) http://i.imgur.com/Pn9QNOE.jpg
C) http://i.imgur.com/P9vzihK.jpg

D) http://i.imgur.com/7lXVCB3.jpg

3) Since the article reported that 56% of business students admitted to cheating at some time during their academic career, you want to establish a hypothesis test to determine if the students at Bayview cheat at a rate less than 56%. What are the appropriate hypotheses for this test?

A) 37
B) 30
C) 26
D) 33

a F 0.05

Explanation / Answer

(1) n = 35, pbar = 0.4111, p = 0.56
Standard error, SE = sqrt(p*(1-p)/n) = sqrt(0.56*0.44/35) = 0.084
test statistics, z = (pbar - p)/SE = (0.4111 - 0.56)/0.084 = -1.773

p-value = 0.03815

As p-value is less than significance level of 0.05, we reject null hypothesis.

(2)
n = 90, pbar = 0.4111, p = 0.56
Standard error, SE = sqrt(p*(1-p)/n) = sqrt(0.56*0.44/90) = 0.052
For 0.05 significance level, z-value = 1.96
Margin of error, ME = z*SE = 0.1026

Lower limit = 0.4111 - 0.1026 = 0.3085
Upper Limit = 0.4111 + 0.1026 = 0.5137

Graph given in option (A) is more accurate with the above values

(3)
H0: p >= 0.56
Ha: p < 0.56

Option (B) is correct

(4)
we need to find n for the p-value = 0.05 and respective z-value is -1.64
-1.64 = (0.4111 - 0.56) / SE
SE = 0.0908

SE = sqrt(p*(1-p)/n)
n = 0.56*0.44/0.0908^2 = 29.886

Hence sample size of 30 is required. Option B