The weight in pouns of ten men, so N = 10 are as follows: 152 196, 144, 139, 166
ID: 3217515 • Letter: T
Question
The weight in pouns of ten men, so N = 10 are as follows: 152 196, 144, 139, 166, 83, 186, 157, 140, 138
Find the Mean of the weight in pounds.
Find the standard deviation of the weight in pounds.
(Deviation) 2
(x-mean)2
Total:
Remember, the standard deviation is the square root of the variance, S2
S2 = Sum (x - x))2 = sum from your third column/N-1
______________
N - 1
What % of this data is within one standard deviation of the mean? Show the interval you used.
What % of this data is within 2 standard deviations of the mean? Show the interval you used.
weight in pounds(S) Deviation from Mean(Deviation) 2
(x-mean)2
Explanation / Answer
from above data
mean =150.1
std deviation =(8610.9/9)1/2 =30.932
hence 1 std deviation away values =(150.1-30.932 ; 150.1+30.932)=(119.168 ; 181.032)
as 7 out of 10 values fall into that interval ; hence 70% of this data is within one standard deviation of the mean
for 2 std deviation away values =(150.1-2*30.932 ; 150.1+2*30.932)=(88.237 ; 211.963)
as 9 out of 10 values fall into that interval ; hence 90% of this data is within one standard deviation of the mean
X (X-mean)^2 152 3.61 196 2106.81 144 37.21 139 123.21 166 252.81 83 4502.41 186 1288.81 157 47.61 140 102.01 138 146.41 total 1501 8610.9 Mean=total/10 150.1Related Questions
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