The efficacy of two kinds of cognitive-behavioral therapy (CBT) in relation to a
ID: 3217167 • Letter: T
Question
The efficacy of two kinds of cognitive-behavioral therapy (CBT) in relation to a clinical population were
compared. The therapies differed on the dimension of how wedded they were to the rational-emotive
behavioral therapy (REBT), a subtype of CBT that emphasizes a directive, confrontational approach to
encourage a patient to recognize the irrationality of specific thought patterns. Forty adolescents at an
inpatient clinic for treatment of self-destructive behaviors were randomly divided into two groups of
equal size, one of which received the less challenging type of CBT (Treatment A) and one of which
received the more challenging kind of CBT (Treatment B). All patients were treated by trained therapists
in one-on-one sessions for 1.5 hours per day (broken down into 45-minute sessions) for six weeks. All
participants were apprised that they were part of a study, all participants signed consent forms, and all
were told they would be informed of the results at its conclusion; participants exhibiting any behaviors
that required critical intervention were promptly treated outside the plan of the study. Outcome data
on the Revised Behavior Problem Checklist (RBPC)-PAR Edition* collected at the conclusion of six weeks
as shown below (also found in the Data Set Scenario 3 Excel file).
Treatment A Treatment B
74 80
50 82
70 49
60 44
30 60
37 65
34 77
40 45
39 51
70 70
19 53
43 16
25 38
15 44
1. Indicate sample size (n = ?), and describe what consequence(s) this sample size will have in terms of analyses and reporting.
2. Using the Choose Your Test document, select a statistical procedure appropriate to your scenario/data. Explain why you selected that test, linking features of the scenario/data to information from the Choose Your Test document.
(Each answer should be a full paragraph explaining your answer)
Explanation / Answer
1.
Here, there are two groups of data and the sample size for each of them is 14 so overall sample size of 28. The samples would play a role in determining the pooled standard deviation and consequently the t-test.
2.
The statitical procedure that would be used in this test would be t-test for two population means because the population is divided into two groups. The same can be calculated as below: -
H0: 1 - 2 = 0
H1: 1 - 2 0
Assuming population variances are equal, we would have to calculate pooled-variance t-Test wherein population 1 are treatment 1 and population 2 are treatment 2: -
Sp^2= (n1-1)S1^2+(n2-1)S2^2/(n1-1)+(n2-1)
= (14-1)*19.12^2+(14-1)*18.39^2/13+13
= 4750.8571+4394.8571/26
=351.7582
tSTAT=(X1-X2)-(µ1-µ2)/Sp^2(1/n1+1/n2)
=(43.29-55.29)-0/351.7582(1/14+1/14)
=-12/7.09
=-1.69
tCRIT is +/-2.055 and hence cannot reject the null hypothesis since tCRIT< tSTAT and falls within the rejection region.
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