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4. Perform an appropriate statistical test to determine if there is a significan

ID: 3205276 • Letter: 4

Question

4. Perform an appropriate statistical test to determine if there is a significant difference in abundance among the four species calculated from the quadrat sampling (5pt). Hint: Use an ANOVA on the raw sampling data.

State Ho and Ha (2pt).

What is your p-value (1pt)?

Do you reject or fail to reject your null hypothesis and why (2pt)?

Group # Quadrat # Species A Species B Species C Species D 1 1 0 0 0 0 1 2 1 0 0 0 1 3 0 0 0 0 1 4 1 1 0 0 1 5 0 0 1 1 1 6 0 0 0 0 1 7 0 0 0 0 1 8 0 0 0 1 1 9 0 0 0 0 1 10 0 0 1 0 1 11 0 0 0 0 1 12 0 0 2 0 1 13 0 0 0 0 1 14 0 0 0 0 1 15 0 0 0 0 1 16 1 0 0 0 1 17 0 0 1 0 1 18 0 0 0 0 1 19 0 1 0 0 1 20 0 0 0 0 1 21 0 0 0 0 2 22 0 0 0 0 2 23 1 0 0 0 2 24 0 0 0 0 2 25 1 0 0 1 2 26 1 0 0 0 2 27 0 0 1 0 2 28 0 0 1 0 2 29 0 0 0 0 2 30 0 0 2 0 2 31 0 2 0 0 2 32 0 0 0 0 2 33 0 1 0 0 2 34 0 1 0 0 2 35 0 0 0 0 2 36 0 0 1 0 2 37 0 0 0 0 2 38 0 1 0 0 2 39 0 0 2 1 2 40 0 2 0 0 2 41 0 1 0 0 3 42 0 0 1 0 3 43 0 0 1 0 3 44 0 0 0 0 3 45 0 0 0 0 3 46 0 0 0 0 3 47 0 0 2 0 3 48 0 0 0 0 3 49 0 0 0 0 3 50 0 1 0 0 3 51 0 0 0 0 3 52 0 0 0 0 3 53 1 0 0 0 3 54 0 1 0 0 3 55 0 0 0 0 3 56 0 0 0 0 3 57 0 0 0 0 3 58 0 0 2 0 3 59 0 1 0 1 3 60 0 0 0 0 3 61 0 0 0 0 4 62 0 0 0 0 4 63 0 0 0 0 4 64 0 0 0 0 4 65 0 0 0 0 4 66 0 0 0 1 4 67 0 0 0 0 4 68 0 0 0 0 4 69 0 0 0 0 4 70 1 0 0 2 4 71 0 0 0 0 4 72 0 0 0 0 4 73 1 0 0 0 4 74 0 2 0 0 4 75 0 0 0 0 4 76 1 0 0 0 4 77 0 0 0 0 4 78 1 0 0 0 4 79 0 0 0 0 4 80 0 0 0 0 4 81 0 1 0 0 5 82 0 0 0 0 5 83 0 1 0 0 5 84 0 0 2 0 5 85 0 0 1 0 5 86 0 0 0 0 5 87 1 1 0 0 5 88 0 0 1 0 5 89 0 0 0 0 5 90 0 0 0 0 5 91 0 0 0 0 5 92 0 0 1 0 5 93 0 0 0 0 5 94 0 0 0 0 5 95 0 0 0 0 5 96 0 0 0 1 5 97 0 0 0 0 5 98 0 0 0 0 5 99 0 0 0 0 5 100 0 0 0 0 5 101 0 0 0 1 6 102 0 0 0 0 6 103 0 0 0 0 6 104 0 1 0 0 6 105 0 0 1 0 6 106 0 0 0 0 6 107 0 0 1 0 6 108 0 0 0 1 6 109 0 0 0 0 6 110 0 0 0 0 6 111 0 0 3 0 6 112 0 0 0 1 6 113 0 0 0 0 6 114 0 0 0 1 6 115 0 0 2 0 6 116 0 0 1 0 6 117 0 0 3 0 6 118 0 0 0 0 6 119 0 0 1 0 6 120 0 0 0 0

Explanation / Answer

Solution:

Here, we have to use the two way analysis of variance for checking the given claim.

The null and alternative hypothesis for this two ANOVA test is given as below:

Null hypothesis: H0: There is no any significant difference in abundance among the four species calculated from the quadrat sampling.

Alternative hypothesis: Ha: There is a significant difference in abundance among the four species calculated from the quadrat sampling.

We assume the level of significance or alpha value for this test as 0.05.

Now, we have to find the test statistic value F by using the ANOVA table calculations.

The ANOVA output for this test is given as below:

Two way ANOVA

Dependent Variable: Abundance

Source

Sum of Squares

df

Mean Square

F

Sig.

Corrected Model

9.153a

23

.398

1.998

.004

Intercept

13.080

1

13.080

65.658

.000

Species

2.934

3

.978

4.909

.002

Group

1.093

5

.219

1.097

.361

Species * Group

5.237

15

.349

1.753

.039

Error

90.845

456

.199

Total

113.000

480

Corrected Total

99.998

479

The P-value for this test is given as 0.004 which is less than the given level of significance or alpha value 0.05, so we reject the null hypothesis that There is no any significant difference in abundance among the four species calculated from the quadrat sampling.

This means we conclude that there is a significant difference in abundance among the four species calculated from the quadrat sampling.

Two way ANOVA

Dependent Variable: Abundance

Source

Sum of Squares

df

Mean Square

F

Sig.

Corrected Model

9.153a

23

.398

1.998

.004

Intercept

13.080

1

13.080

65.658

.000

Species

2.934

3

.978

4.909

.002

Group

1.093

5

.219

1.097

.361

Species * Group

5.237

15

.349

1.753

.039

Error

90.845

456

.199

Total

113.000

480

Corrected Total

99.998

479

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