PLEASE SOMEONE HELP AND ANSWER CORRECTLY ITS DUE TODAY !!!!! 2. O 0.753 points I
ID: 3200553 • Letter: P
Question
PLEASE SOMEONE HELP AND ANSWER CORRECTLY ITS DUE TODAY !!!!! 2. O 0.753 points I Previous Answers PODStat4 11.E.010 My Notes o Ask Your Teache Each person in a random sample of 228 male teenagers and a random sample of 302 female teenagers was asked how many hours he or she spent online in a typical week. The sample mean and standard deviation were 15.1 hours and 11.3 hours for males and 14.1 and 11.8 for females. (Use a statistical computer package to calculate the P-value. use Aumale Aufemales Round your test statistic to two decimal places, your df down to the nearest whole number, and your P-value to three decimal places.) Is there enough evidence to show that mean number of hours spent online in a typical week is greater for male teenagersExplanation / Answer
Let u1 = mean number of hours spent online by a typical male teenager
. Let u2 = mean number of hours spent online by a typical female teenager.
n1=228 , x1 = 15.1, s1=11.3
n2=302,x1=14.1 s1=11.8
t = (15.1-14.1)/sqrt(11.3^2/228 + 11.8^2/302)
= 0.9896
df = (s1^2/n1 + s2^2/n2)/ ((1/n-1)(s1^2/n1)^2) + ((1/n2-1)(s2^2/n2))
= 1.04265/(0.001382+0.00070623)
= 499.29 = 499
P-value = 0.1614
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