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2 and 3 pls quick help Name, Surname Group 1 2 3 4 5 6 7 8 9 10 Total Grade ALPE

ID: 3200280 • Letter: 2

Question


2 and 3 pls quick help

Name, Surname Group 1 2 3 4 5 6 7 8 9 10 Total Grade ALPER Tot Probability Theory and Mathematical statistics Final examination Variant 1 1. Among Part 1. Random Events five 18 computers in some store, 6 have defects. 5 randomly selected computers are bought for the university lab. Compute the probabaty tat al computers have no defects. 2. The probability that a component is not standard is o.04. Compute the probability that among 20 components not more than 2 are nonstandard 3. A computer assembling company receives 24% of parts from supplier X, 36% of parts from supplier Y. and the remaining 40% of parts from supplier z 5% of parts supplied by x, 10% of parts supplied by Y, and 6% of parts supplied by z are detective. If an assembled mputer has a defective part in a, co what is the probability that this part was received from supplier Z? Part 2. Random Variabl 4. Two independent random variables x y are given with their distribution laws and 0.1 0.9 0.3 0.4 0.3 Find the distribution law and expected value for the random variable z 2xY+2 will be co 5. A computer virus is trying to corrupt 3 files. The first file will be corrupted with the probability Independently of t, the second file of with the probability 2. Independently of it, the third file will be corrupted with the o 3. Construct law files. Let X be a continuous random variable whose cumulative distribution function is: If 0sxs 2, F (x)

Explanation / Answer

2) The probability that a component is not standard is .04
Therefore, prob that a component is standard is 1-.04 = .96

But we are being asked a question: Prob among 20 components not more than 2 are non-standard?

P(X<=2)

= P(X=0)+P(X=1)+P(X=2)

=20C0(.04)^0(1-.04)^20 +...20C2(.04)^2(1-.04)^(20-2)

=0.9561

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