Based on the information provided in the output below, what is the correct decis
ID: 3183450 • Letter: B
Question
Based on the information provided in the output below, what is the correct decision ?
Reject the null hypothesis at the 0.10 level of significance
Reject the null hypothesis at the 0.05 level of significance
Do not reject the null hypothesis
Both A & B
What conclusion can be made from this decision?
There is not enough statistical evidence to infer that the new process has reduced production time.
There is enough statistical evidence to infer that the new process as reduced production time.
There is enough statistical evidence to infer that the new process has increased production ime
There is not enough statistical evidence to infer that the new process as increased productino time
What is the test statistic when the appropriate analysis is done?
.796
-5.93
-5.805
2.348
What is the p-value of this test?
.1473
.0000
about 1.00
would need to consult z-table
What was the hypothesized probability of a Type 1 Error?
.98
.02
.01
.99
Reject the null hypothesis at the 0.10 level of significance
Reject the null hypothesis at the 0.05 level of significance
Do not reject the null hypothesis
Both A & B
What conclusion can be made from this decision?
There is not enough statistical evidence to infer that the new process has reduced production time.
There is enough statistical evidence to infer that the new process as reduced production time.
There is enough statistical evidence to infer that the new process has increased production ime
There is not enough statistical evidence to infer that the new process as increased productino time
What is the test statistic when the appropriate analysis is done?
.796
-5.93
-5.805
2.348
What is the p-value of this test?
.1473
.0000
about 1.00
would need to consult z-table
What was the hypothesized probability of a Type 1 Error?
.98
.02
.01
.99
F-Test Two-Sample for Variances t-Test: Paired Two Sample for Means New Old Process New Process Old Process Process Mean 46.814 46.814. 48.116 Mean 48.116 1.918 2.410 Variance 1.918 2.410 Variance 86 86 Observations 86 86 Observations df 85 85 Pearson Correlation 0.043 F Hypothesized Mean Difference 0.796 P(FK f) one-tail 0.147 df 85.000 0.698 t stat -5.934 F Critical one-tail 0.000 P(TK-t) one-tail 2.371 t Critical one-tail PT t) two-tail 0.000 t-Test: Two-Sample Assuming Unequal variances t critical two-tail Old Process New Process 46.814 t-Test: Two-Sample Assuming Equal Variances Mean 48.116 variance 1.918 2.410 86 86 Old Process New Process Observations Hypothesized Mean Difference 46.814 Mean 48.116 ldf 168 Variance 1.918 2.410 stat -5.805 Observations 86 86 p(TK-t) one-tail 0.000 Pooled Variance 2.164 tcritical one-tail 2.349 Hypothesized Mean Difference Ft) two-tail 0.000 Idf 170.0000 2.605 tstat -5.805 t Critical two-tail 0.000 p(TExplanation / Answer
Answer:
A). Do not reject the null hypothesis ( F test is not significant)
B). Reject the null hypothesis at the 0.05 level of significance ( t test equal variance is significant)
Both A & B
What conclusion can be made from this decision?
There is enough statistical evidence to infer that the new process has increased production time
What is the test statistic when the appropriate analysis is done?
-5.805
What is the p-value of this test?
0.000
would need to consult z-table
No
What was the hypothesized probability of a Type 1 Error?
0.01
There is enough statistical evidence to infer that the new process has increased production time
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