The city of Tucson, Arizona, employs people to assess the value of homes for the

Question

The city of Tucson, Arizona, employs people to assess the value of homes for the purpose of establishing real estate tax. The city manager sends each assessor to the same five homes and then compares the results. The information is given below, in thousands of dollars. Can we conclude that there is a difference in the assessors? Use the 0.05 significance level.

Assessor

a.

Is there a difference in the treatment means? (Round your answer to 2 decimal places.)

The computed F value is

b.

Is there a difference in the block means? (Round your answer to 2 decimal places.)

The computed F is

Home Zawodny Norman Cingle Holiday A $57 $51 $48 $42 B   58   53   52   56 C   42   55   45   57 D   71   64   63   64 E   84   89   93   85

a.

Is there a difference in the treatment means? (Round your answer to 2 decimal places.)

The computed F value is

b.

Is there a difference in the block means? (Round your answer to 2 decimal places.)

The computed F is

Explanation / Answer

a)

H0: There is no significance difference between all the treatments

H1:There is a significance difference between all the treatments

H0: There is no significance difference between all the blocks

H1:There is a significance difference between all the blocks

alpha:5%

From Excel

F cal =33.02 (Treatments)

F cal= 0.202 (Blocks)

Conclusion:

For Treatments: P value=0.00000217 < 0.05, we reject H0. Hence claim is signifacant

For Blocks: P value=0.8930 >0.05, we do not reject H0. Hence claim is not significant

Anova: Two-Factor Without Replication SUMMARY Count Sum Average Variance A 4 198 49.5 39 B 4 219 54.75 7.583333 C 4 199 49.75 54.25 D 4 262 65.5 13.66667 E 4 351 87.75 16.91667 Z 5 312 62.4 251.3 N 5 312 62.4 245.8 C 5 301 60.2 382.7 H 5 304 60.8 246.7 ANOVA Source of Variation SS df MS F P-value F crit Rows 4130.7 4 1032.675 33.01918 2.17E-06 3.259167 Columns 18.95 3 6.316667 0.201972 0.893031 3.490295 Error 375.3 12 31.275 Total 4524.95 19

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