3 (a-g) thanks a. If one of the 611 challenges is randomly selected, what is the
ID: 3182315 • Letter: 3
Question
3 (a-g)
thanks
Explanation / Answer
Following is the completed table:
(a)
Since out of 611 challenges, 172 are overturned so requried probability is
P(upheld) = 172/611 = 0.2815
(b)
Out of 400 challenges made by men, 121 are overturned so required probability is
P(overturned|men) = 121/400 = 0.3025
(c)
Out of 211 challenges made by women, 51 are overturned so required probability is
P(overturned | women) = 51/211 = 0.2417
(d)
Out of 172 overturned challenges, 51 are made by women so required probability is
P(women | overturned) = 51/172 = 0.2965
(e)
The requried probability is
P(both are overturened) = (172/611)*(172/611) = 0.0792
(f)
P(man)= 400/611
P(overturned) = 172/611
P(man and overturned) = 121/611
So required probability is
P(man or overturned) = P(man)+P(overturned) - P(man and overturned) = 0.7381
(g)
P(man | overturned) = 121/172 = 0.7035
Challenge Upheld with overturned call Challenge Rejected with No change Total Challenges are Men 121 279 400 Challenges are Women 51 160 211 Total 172 439 611Related Questions
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