5) Find the area under the standard normal curve between z = -1.50 and z = 2.50.

ID: 3181267 • Letter: 5

Question

a) 0.7182 b) 0.6312 c) 0.9831 d) 0.9270

6) Find the area under the standard normal curve to the right of z = -1.25

a) 0.6978 b) 0.8944 c) 0.7193 d) 0.5843

7) For a standard normal curve, find the z-score that separates the bottom 90% from the top 10%

a) 2.81 b) 1.52 c) 0.28 d) 1.28

8) Find the z-scores for which 90% of the distribution’s area lies between -z and z

a) (-0.99, 0.99) b) (-1.645, 1.645) c) (-2.33, 2.33) d) (-1.96, 1.96)

9) Find the z-score that is less than the mean and for which 70% of the distribution’s area lies to it’s right.

a) -0.52 b) -0.47 c) -0.81 d) -0.98

using z table

p value for z= -1.5 is 0.066807

p value for z= 2.5 is 0.99379

area under the standard normal curve between z = -1.50 and z = 2.50. = 0.99379-0.066807 = 0.926983 = 0.9270

p value for z= -1.25 is 0.10565

area under the standard normal curve to the left of z = -1.25 is 0.10565

area under the standard normal curve to the right of z = -1.25 is 1- 0.10565 = 0.89435

z value for 90%or 0.9 is 1.281551

z-score that separates the bottom 90% from the top 10% is 1.28

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