answers are a. .5420 b. .0508 c. .4912 p .5928 I just need to see all work, than

Question

answers are

a. .5420

b. .0508

c. .4912 p .5928

I just need to see all work, thanks!

8. A USA Today/CNN Gallup survey of 369 working parents found 200 who said they spend too little time with their children because of work commitments a. What is the point estimate of the proportion of the population of working parents who feel they spend too little time with their children because of work commitments? b. At a 95% confidence level, what is the margin of error? c. What is the 95% confidence interval estimate of the population proportion of working parents who feel they spend too little time with their children because of work commitments?

Explanation / Answer

Part a)

We are given,

n = 369

x = 200

P^ = x / n

     = 200 / 369

     = 0.5420

Answer: 0.5420

Part b)

E = zc * Ö[ (p^*(1-p^)) / n]

The critical z value for 5% (100-95%) level of significance we get from Normal Table as 1.96

E = 1.96 *Ö [ ( 0.5420 * (1-0.5420))/369)]

= 1.96 * Ö0.0006727

= 1.96 * 0.02594

= 0.0508

Answer: 0.0508

Part c)

P^ (-/+) E

= 0.5420 (-/+) 0.0508

= (0.5420 – 0.0508 ) and (0.5420 + 0.0508 )

= 0.4912 and 0.5928

Answers: 0.4912 p 0.5928

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