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1. The quality-control manager at a lightbulb factor needs to determine whether

ID: 3179958 • Letter: 1

Question

1. The quality-control manager at a lightbulb factor needs to determine whether the mean life of a large shipment of lightbulbs is equal to 375 hours. The population standard deviation is 100 hours. A random sample of 64 lightbulbs indicates a sample mean life of 350 hours. a. At the 0.05 level of significance is there evidence that the mean life is different from 375 hours? b. Compute the p-value and interpret its meaning. c. Construct a 95% confidence interval estimate of the population mean life of the lightbulbs.

Explanation / Answer

H0 :  = 375

H1  : 375 (claim)

= 0.05 (significance level)

/2= 0.025(two-tailed)

A. Since the key word "different" is the question, then this is a two-tailed test. Therefore, divide 0.05 by 2 = .025(per tail). We find the critical values by going to the z-score tables for normal distribution.

Notice that the area= .025 corresponds to z-scores(critical values)= ±1.96.

To calculate test-statistic manually: (350-375)/(120/64) =-25/15= -1.66 .

Since the test-statistic does not land within the critical values region, then we can conclude at a 0.05 significance level that there is not sufficient evidence to support the claim that the mean life is different from 375 hours.

B. Using Graphing calculator TI-83: go to STATS, TESTS, Z-Test, Stats, 0:375, :120, x:350, n:64, : 0, CALCULATE. p-value=.096 which is greater than =0.05.

Therefore we support the null hypothesis(H0)and reject the claim of the alternative hypothesis(H1).

C .Using graphing calculator TI-83: STATS, TESTS,7ZInterval...,Stats, :120, x:350, n:64, C-Level:.95,          Calculate= (320.6, 379.4)