The following table shows the results of a study on smoking and three illnesses.
ID: 3179579 • Letter: T
Question
The following table shows the results of a study on smoking and three illnesses. We are interested in
determining if the proportions of smokers in the three categories are different from each other.
Data was collected in the table below and expected frequencies were also calculated.
Emphysema Heart problem Cancer Total
Smoker 150 70 100 320
Non-smoker 50 130 500 680
Total 200 200 600 1000
Emphysema Heart problem Cancer
Smoker 64 64 192
Non-smoker 136 136 408
Use alpha = .05.
Ho: pE = pH = pC Ha: not as above
Show your work in calculating X(2) chi-square statistic.
Critical value =
Conclusion of Test:
Use a CV critical value to determine if there is a significant difference between the percentages of people
who have heart problems that are smokers and the percentage of people who have cancer that are smokers.
pH = 70 / 200 .35
pC = 100 / 600 .167
Explanation / Answer
here chi stat =235.6
for above 2 degree of freedom critical vcalue of Chi square =5.9915
as chi stat is very much higher then critical value we conclude proportions of smokers in the three categories are different from each other
Observed O Emphysema Heart Problem Cancer Total Smoker 150 70 100 320 Non -Smoker 50 130 500 680 Total 200 200 600 1000 Expected E=rowtotal*column total/grand total Emphysema Heart Problem Cancer Total Smoker 64.000 64.000 192.000 320 Non -Smoker 136.000 136.000 408.000 680 Total 200 200 600 1000 chi square =(O-E)^2/E Emphysema Heart Problem Cancer Total Smoker 115.563 0.563 44.083 160.208 Non -Smoker 54.382 0.265 20.745 75.392 Total 169.945 0.827 64.828 235.600Related Questions
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