Young Professional magazine was developed for a target audience of recent colleg

Question

Young Professional magazine was developed for a target audience of recent college graduates who are in their first 10 years of a business or other professional career. The magazine has been fairly successful and the publisher is interested in expanding the publication’s advertising base. As a recent hire into the marketing department at the magazine, you have been asked to help develop a survey asking readers demographic information and questions about their interests. Your survey results will be used to help the magazine choose articles of interest and provide advertisers with a profile of subscribers.

The culmination of your work will be a presentation of your findings to management. Therefore, you not only have to present summary data, but must also be able to explain the results in a manner that is accurate and easy to understand.

1) Your analysis returned the following information about subscriber income:

2) Based on the following results of your survey, how confident are you that a majority of the magazine’s subscribers have broadband access?

3) After running your analysis, the software returns the following information about the age of the respondents:

N Mean variable StDev LSE Mean Income 410 I 74459.5 34818.2 1719.5 Using this information, compute the margin of error for 90%, 95%, and 99% confidence intervals for mean household income. O a. t2971.5, +3540.5, and t3905.5 b. 2828.6, 13370.3, and t 4429.6 c. +2870.4 3420.5, and t4494.9

Explanation / Answer

1) at 90% ; z=1.64485

at 95%; z =1.96

at 99%; z=2.5758

hence margin of errror =z*std error

option B is correct

2)p=256/410=0.624

which is extremely significant comared to 0.501 and vary far as std error is very low

option C is correct

3)option b is correct

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