A. Calculate the number of different random samples of size 9 (n) that can be se
ID: 3173870 • Letter: A
Question
A. Calculate the number of different random samples of size 9 (n) that can be selected from a finite population of size 22 (N). Enter your response as an integer. Use the COMBIN function.
B. Calculate the point estimate (sample statistic, xbar) of the population mean using the following values from a randomly selected sample (9.32, 3.603, 4.6771, 4.146, 3.17, 4.737, 6.8984) and enter your response to two decimals (i.e. 1.12).
C. Calculate the difference (absolute value) between the point estimate 32.6 (xbar, sample mean, the statistic) and the parameter 26 (mu, population mean). Enter your response to one decimal.
D. Calculate the standard deviation of the distribution of sample means (standard error of of the mean) where the population standard deviation (sigma) is 8.732 and the size of the sample to be selected (n) is 200. Assume the population is very large. Enter your response to four decimals (i.e. 1.1234).
E. Calculate the standard deviation of the distribution of sample means (standard error of the mean) where the population variance (sigma squared) is 16 and the size of the samples (n) is 186 for a population (N) of 726. Enter your response to four decimals (i.e. 1.1234). (hint: use the finite population correction factor)
F. Determine the probability of a sample mean being at least 1.32 standard deviations greater than the population mean. Assume the central limit theorem applies and enter your response as a probability to four decimals (i.e. 0.1234). Use the NORMSDIST function.
G. Determine the probability of a sample mean being within plus or minus 3 (of the population parameter) where the population mean is 49.3, the sample size is 83, the population standard deviation (sigma) is 14.9, and the population is very large. Enter your response as a probability to two decimals (i.e. 0.12). Use the NORMDIST function.
H. Determine how many standard deviations (z) the sample mean (xbar = 15.8), from a sample (n) of 32, is from the population mean (mu = 9.2) for a large population, where the population standard deviation (sigma) is 5.8. Enter your response to two decimals (i.e. 0.12), as you would use to determine probabilities from the standard normal distribution table in the textbook.
I. Calculate the sample proportion (pbar, estimate of the population proportion) where 291 (x) exhibited the attribute/characteristic of interest in a sample of 2,602 (n). Enter your response to three decimals (i.e. 0.123).
J. Calculate the difference (absolute "positive" value) between the point estimate (pbar) and the parameter (p) where the proportion in the population for the outcome of interest is 0.47 (population parameter, p) and the number in a sample of 1,006 that are the outcome of interest is 373. Enter your response to two decimals (i.e. 0.12).
K. Calculate the standard deviation of the distribution of sample proportions (sigma pbar) where the proportion in the population exhibiting the attribute/characteristic of interest is 0.25 and the size for the samples is 523. Assume the population is very large. Enter your response to four decimals (i.e. 0.1234).
L. Calculate the standard deviation of the distribution of sample proportions (sigma pbar) where the proportion in the population exhibiting the attribute/characteristic of interest is 0.37, the size of the samples to be selected are 247, and the population size is 1,191. Enter your response to four decimals (i.e. 0.1234). (hint: use the finite population correction factor as n/N>.05)
M. Determine the probability of a sample proportion yielding a z value of 2.05 (standard deviations of the proportion) or less. Enter your response as a probability to four decimals (i.e. 0.1234). Use NORMSDIST function.
N. Determine the probability of a sample proportion being within plus or minus 0.03 (of the population parameter) where the population proportion is 0.69, the sample size is 902, and the population is very large. Enter your response as a probability to two decimals (i.e. 0.12).
O. Determine how many standard deviations (z) the sample proportion with (163) exhibiting the attribute/characteristic of interest from a sample of 338 is from the population proportion (0.62) for a very large population. Enter your response as the absolute (positive) value, to two decimals (i.e. 0.12).
Explanation / Answer
(A) Number of samples = C(22, 9) = 497420
(B) Mean = sum of data/number of data = 5.22
(C)Difference = 32.6 - 26 = 6.6
(D) Standard deviation = /n = 8.732/200 = 0.6174
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