54 Alice Chang and her colleagues (A. Chang, L. Rosenthal. R. H. Bryant, R. H. R
ID: 3173005 • Letter: 5
Question
54 Alice Chang and her colleagues (A. Chang, L. Rosenthal. R. H. Bryant, R. H. Rosenthal, R. M. Heidlage, and B. K. Fritzler. "Comparing High School and College Students' Leisure In- terests and Stress Ratings," Behavioral Research Therapy 31(2), 1993) tested 559 high school students using a leisure-interest checklist (LIC) survey. The means and standard deviations for each of the seven LIC factor scales are given in the following table for n 252 male students and n 307 female students a Give a 95% confidence interval for the difference in the means for male and female stu- dents for the cultural activity scale. Interpret this interval.Explanation / Answer
Solution:
We are given n = 252 for male and n = 307 for female
The confidence interval formula is given as below:
Confidence interval = (X1bar – X2bar) -/+ t*[(S1^2/N1)+(S2^2/N2)]
Where, t is the critical value.
Part a
Here, we have to find 95% confidence interval for difference in the means for male and female for cultural activity.
We are given
X1bar = 11.48
X2bar = 13.21
S1 = 5.69
S2 = 5.31
N1 = 252
N2 = 307
Degrees of freedom = 252 + 307 – 2 = 557
Confidence level = 95%
Critical t value = 1.9642
Confidence interval = (11.48 – 13.21) -/+ 1.9642*sqrt[(5.69^2/252)+(5.31^2/307)]
Confidence interval = -1.73 -/+ 0.921962
Lower limit = -1.73 - 0.921962 = -2.65196
Upper limit = -1.73 + 0.921962 = -0.80804
Confidence interval = (-2.65196, -0.80804)
Part b
Here, we have to find the 90% confidence interval for difference in means for social fun.
We are given
X1bar = 22.05
X2bar = 25.96
S1 = 5.12
S2 = 5.07
N1 = 252
N2 = 307
Degrees of freedom = 252 + 307 – 2 = 557
Confidence level = 90%
Critical t value = 1.6476
Confidence interval = (22.05 – 25.96) -/+ 1.6476*sqrt[(5.12^2/252)+(5.07^2/307)]
Confidence interval = -3.91 -/+ 0.713916
Lower limit = -3.91 - 0.713916 = -4.62392
Upper limit = -3.91 + 0.713916 = -3.19608
Confidence interval = (-4.62392, -3.19608)
Part c
Yes, means for males and females for the two LIC activities appeared to differ because the value 0 does not lies within this interval.
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