53. An object is launched upward at the height of 360 meters. It\'s height can b

Question

53. An object is launched upward at the height of 360 meters. It's height can be modeled by h--4.9t2 + 50t + 360, where h stands for the object's height in meters, and t stands for time passed in seconds since its launch The object's height will be-400 meters twice before it hits the ground. Find how many seconds since the launch would the ob- ject's height be 400 meters. Round your answers to two decimal places if needed The object's height would be 400 meters the first time at and then the second time at seconds. seconds

Explanation / Answer

Solve h(t) =400

-4.9t² +50t+360 =400

4.9t² -50t +40 =0

Using Quadratic formula

t= (50 -sqrt(50² -4*4.9 *40))/(2*4.9) , (50 +sqrt(50² -4*4.9 *40))/(2*4.9)

t= 0.88, 9.33

hence first time at 0.88 seocnds and second time at 9.33 seconds

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