Previous Work Done as Reference: The value of r2 is 0.9951 and the value of r is

Question

Previous Work Done as Reference:

The value of r2 is 0.9951 and the value of r is 0.9975

The regression equation can be formed using the variables that are signifcant . that is , whose p values are less than 0.05 , considering an alpha of 0.05

so we get the equation as (only L and N are signifcant as the p values are less than 0.05 )

WT = 2.77*L + 0.42*N

so only length and number of parts are important statistically

b. Do you think the equation fits the data well, based on the r value? (Give a yesno and a reason.) c. Define the range of values for length, thickness, and number of parts for which your equation is valid. d. Demonstrate how good the system is in predicting time standards by calculating the difference between the times in the table and your predicted time for each model. Show these in a table. Summarize your thoughts on how good the system is (would you trust it to manage production?)

Explanation / Answer

b) Yes , as the r2 value is 0.96 hence the model is able to explain approximately 96% variation of the data , hence yes the model fits the data very well.

c)

The range is defined as the difference of the maximum and the minimum value of the variable. so we need to calculate the range for all the 3 independent variables in question

Length 4.75(max) - 0.68(min) = 4.07, covers data from 0.68 to 4.75

N = number of parts range from 2 to 8

T = thickness range from 6 to 10

d) it is not clear which other models the questions refer to apart from the regression model built above for comparison

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.