1. At high concentrations, inorganic fluoride inhibits enolase. In an anaerobic
ID: 3166803 • Letter: 1
Question
1. At high concentrations, inorganic fluoride inhibits enolase. In an anaerobic system that is metabolizing glucose as a substrate, which of the following compounds would you expect to immediately increase in concentration following the addition of fluoride?
A. 2-phosphoglycerate.
B. Glucose.
C. 3-phosphoglycerate
D. Phosphoenolpyruvate
E. Pyruvate
2. Suppose you have 1X10 -6 moles of radioactive ATP where only the alpha phosphate group is radioactive (i.e. P-P-*P-suger-base, where the * indicates the radioactive phosphorous atom). If you add all the radioactive ATP to a tube containing hexokinase and 1X10 -6 moles of glucose, what percentage of phosphorylated glucose molecules would you expect to be radioactive after an appropriate amount of incubation?
A.
100%
B.
0%
C.
50% because at equilibrium the concentration of glucose and glucose-6-phosphate will be equal
D.
Impossible to tell
E.
Somewhere between 50-100% because the equilibrium does favor glucose-6-phosphate, but some glucose and ATP will remain.
3. The fate of pyruvate produced during glycolysis depends primarily on the availability of:
A.
NAD+ to keep the pathway going.
B.
Diatomic oxygen.
C.
ADP for conversion to ATP.
D.
Coenzyme A for further metabolism of pyruvate.
E.
Inorganic phosphate for the synthesis of ATP.
4. The anaerobic conversion of 1 mol of glucose to 2 mol of lactate by fermentation is accompanied by a net gain of:
A. 1 mol of ATP.
B. 1 mol of NADH.
C. 2 mol of ATP.
D. 2 mol of NADH.
E. None of the above
5. Starting from glucose, UTP and ATP, how many high-energy phosphate bonds are broken to add glucose to a glycogen molecule?
A.
1
B.
2
C.
3
D.
4
E.
The answer cannot be determined form the information given
A.
100%
B.
0%
C.
50% because at equilibrium the concentration of glucose and glucose-6-phosphate will be equal
D.
Impossible to tell
E.
Somewhere between 50-100% because the equilibrium does favor glucose-6-phosphate, but some glucose and ATP will remain.
Explanation / Answer
1.the correct answer is 2-phosphoglycerate
2.somwhere between 50 - 100 %
3.availability of diatomic oxygen
4.2 mol of ATP
5.3 phoshate bonds are broken
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