a colorblind man marries a woman with normal vision of the woman is not a carrie

Question

a colorblind man marries a woman with normal vision of the woman is not a carrier of the colorblind gene BIO 181 Genetics Problem Set Spring 2018 Part B. Sex linked genes and codominance. In humans, the gene for red green colorblindness is carried on the X chromosome (X is used for normal vision, XC is used for a colorblind allele, Y is used for the Y chromosome). This means if a male inherits the colorblind gene from his mother, he wil be colorblind. For a female to be colorblind she must inherit the colorblind gene from her mother and her father. A Punnett Square for a male with normal vision (XY) having children with a female that is colorblind (XCXC) would look as follows In this case, the female offspring would all be carriers and the male offspring would all be colorblind 1. A colorblind man marries a woman with normal vision. If the woman is not a carrier of the colorblind gene, what would you expect the phenotypic ratio to be in their offspring? 2. A colorblind man marries a woman who is a carrier of the colorblind gene. would you expect the phenotypic ratio to be in their offspring? What

Explanation / Answer

Answer 1:

A colorblind man marries a woman with normal vision and woman is not a carrier

Ratio: Normal 1 : 0 Colorblind

Please refer the below punnet

Answer 2:

A colorblind man marries a woman with normal vision and woman is a carrier

Ratio: Colorblind male 1: Colorblind female 1: Normal male 1: Normal female 1 (but normal woman will be carrier)

XC Y X XCX XY X XC?X XY

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