A charge of 27.0 nC is placed in a uniform electric field that is directed verti

Question

A charge of 27.0 nC is placed in a uniform electric field that is directed vertically upward and has a magnitude of 3.50 times 10^4 V/m. For related problemsolving tips and strategies, you may want to view a video Tutor Solution of Electric force and electric potential. What work is done by the electric force when the charge moves a distance of 0.470 m to right? What work is done by the electric force when the charge moves a distance of 0.670 m upward? What work is done by the electric force when the charge moves a distance of 2.80 m at an angle of 45.0 degree downward from the horizontal?

Explanation / Answer

Part A] When the charge moves horizontally, the work done will be: W = (qE)Scos0o = 0 J.

Part B] W = qE(0.670) = 27.0 x 10-9 x 3.5 x 104 x 0.670 = 6.3315 x 10-4 J

Part C] W = - qE(2.8cos45) = - 1.871 x 10-3 J.

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