Lateral raise - 25 pounds resistance (R) = 25 Distance from shoulder joint to ha
ID: 3163772 • Letter: L
Question
Lateral raise - 25 pounds resistance (R) = 25 Distance from shoulder joint to hand = 54 cm Distance from shoulder joint to where deltoid attaches = 9cm What is the minimum amount of force needed by the deltoid to lift this weight? Calf muscles on one leg can generate 360 lbs of force Distance from the joint of your toe to the heal, where the muscle attaches = 25cm Distance from the joint of your toes with your foot to where your tibia forces weight down on your foot = 22cm If you stood on one leg and then used your calf muscles to lift yourself onto the ball of your foot, what is the maximum amount of weight you could lift on one leg? resistance (R) Right bicep can generate 225 lbs of force The distance from your elbow joint to the hand where you are holding the dumbbell = 30cm The distance from your elbow joint to the insertion of the biceps = 5cm What is the maximum amount of weight that you can lift with that arm?Explanation / Answer
2] Net torque is zero when the force is minimum.
Taking torque about the shoulder joint, we get:
25 lbs = 11.34 kg
- 0.54(11.34 x 9.8) + F(0.09) = 0
=> F = 666.792 N.
4]
The net torque will be zero for such a case.
The force due to the bicep is vertically upwards.
225 lbs force = 1000.85 N
Therefore, taking the torque about the elbow joint, we get:
1000.85(0.05) - mg(0.3) = 0
=> m = 17.02 kg = 37.52 pounds.
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