Lat eli) e kl, calculate the unit tanannt vector. Three-dimensional motion Consi
ID: 2875639 • Letter: L
Question
Lat eli) e kl, calculate the unit tanannt vector. Three-dimensional motion Consider the motion of the follo ing objects. Assume the x-axis points east, the y-axis points north, t positive z-axis is vertical and opposite g. the ground is horizontal, a only the gravitational force acts on the object unless otherwise stat a. Find the velocity and position vectors for, t 2 0. b Determine the time offtight and range of the object. Determine the maximum height of the object. A baseball is hit 3 ft above home plate with an initial velocity of K30. 30, 80) ft/s. The spin on the baseball produces a borizontal acceleration of the ball of 5 ft/s in the northward direction.Explanation / Answer
22)
We use the kinematic equations of motions in each of the three directions,i.e
v=u+at, s=ut+(1/2)at2 , and v2=u2+2as
Given ax=0, ay=5, az=-32.174
vx=ux+axt
vx=30
vy=30+5t and vz=80-32.174t
Similarly for position vectors
Sx=uxt+(1/2)axt2=30t ,
Sy= 30t+(1/2)(5)t2 , and Sz= 80t-(1/2)(32.174)t2
Now, the flight ends when the ball reaches the ground, or in other words Sz=-3
Substituting Sz=-3 we get,
-3=80t-(1/2)(32.174)t2
Therefore t=5.01,-0.037
since time cant be negative time of flight t=5.01s.
Substituting this t in Sx and Sy we get Sx=150.3ft and Sy=213.05ft which is the required range.
Now,
maximum height will be reached when vz=0
Using v2=u2+2as
we get, 0=uz2+2azS
Sz=-uz2/2az = -(802)/(2)(-32.174) = 99.456ft
Therefore maximum height will be 99.456+3=102.459ft. as it started from 3ft height.
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