please answer it with good presentation that I can read and understand clearly.
ID: 3163736 • Letter: P
Question
please answer it with good presentation that I can read and understand clearly. Thank you.
Some large river dams are built with fish locks to allow fish to migrate past the dams. The fish lock is essentially a water filled elevator open at the top (see pictures below of a fish lift installed on Paradise Dam in Queensland). Consider a rectangular fish lift, with a base of 2.8 metres by 1.5 metres, and filled with water to a height of 1.7 metres. The lift accelerates up and down the dam wall, inclined at 30 degree from the vertical, at a constant acceleration of 1.4 m/s^2 along the incline, calculate: The total hydrostatic thrust on the base of the fish lift as the lift moves up and down the incline. Calculate the required freeboard above the water height of 1.7 metres to ensure no water is spilled while the fish lift moves. Consider the fish lift moving up and down and with both the short and long side of the base parallel to the dam wall. Identify the worst case scenario. Ignore the weight of the fish in the lift in your calculations.Explanation / Answer
The Area of Rectangle fish lift is (A) = 4.2 m2
F = phA = 1000* 9.81 * ( 1.7 + 0.3* sin 30) * 4.2 = 9810 * 1.40 * 4.2 = 57682.8 N
F = 57682.8 N
Now we find the distance d where the force F acts from the hinge:
y= h/sin30 = 1.7 + 0.3* sin 30 / sin 30 = 2 m
Yp = y+Is/ Ay = 2 + 2.8 * 1.53 / 1.7* ( 2.8 * 1.5) * 2 = 48.69 m , where Is is second movement area on x- axis
d = 0.3 - ( Yp - y) = 0.3 * (48.69 - 2) = 14 m
The force P can be calculated
P = d * F/a = 14* 57682.8/ 4.2 = 192276 N
Freeboard Depth = 1.7 m
Freeboard abve the water = D + Thickness of lift
= 1.7+ 4.2
= 5.9
Correctin = 5.9 +0.68/ 1.36
= 6.4
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