Use the figure at the right to answer questions 11 and 12. R_1 = 19 k Ohm, R_2 =

Question

Use the figure at the right to answer questions 11 and 12. R_1 = 19 k Ohm, R_2 = 39 k Ohm, R_3 = 29 k Ohm and C = 1800 mu F. sigma = 17 kv. Assume that the capacitor is completely uncharged before switch S is closed. [10]#11. Circle the letter(s) corresponding to the TRUE statement(s) below. Statements: A long time after the switch is closed the current in R_3 is at a maximum value. A long time after the switch is closed the current in R_2 is exactly the same as the current in R_1 Immediately after the switch S is closed, the capacitor behaves as if there is a"wire connection (ie., a short circuit)" in the if branch between alpha and beta. Referring to the circuit, "a long time after the switch S is closed" means that more than 30 minutes must pass the switch is closed. Immediately after the switch S is closed, the capacitor behaves as if the lower end of R_2is left unconnected from the circuit.

Explanation / Answer

(a) True, As capacitor will act as broken wire, means no current through R2. hence maximum current will flow through R3.

(b)False, current through R2 will be zero(0).

(c)True, q=cV , at t=0, q=0, so, Voltage drop across it will be zero.

(d)False, a long time after means infinite time. as V across capactior is exponential function.

(e)False, immedidetely after , it will act like short circuit across capacitor.

so, (a) and (c) are true.

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