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The displacement of a string carrying a travelling sinusoidal wave is given by y

ID: 3162335 • Letter: T

Question

The displacement of a string carrying a travelling sinusoidal wave is given by y (x, t) = y_m sin (kx - omega t - Phi). At time t = 0 the point at x = 0 has a displacement of 0 and is moving in the negative y direction. The phase constant Phi is: 45 degree 180 degree 135 degree 0 degree None of listed Sinusoidal waves travel on five identical strings. Four of the strings have the same tension, but the fifth has a different tension. Use the mathematical forms of the waves, give below, to identify the string with the different tension. In the expressions given below x and y in centimeters and t is in seconds. y (x, t) = (2 cm) sin (2x - 4t) y (x, t) = (2 cm) sin (5x - 10 t) y (x, t) = (2 cm) sin (4x - 12 t) y (x, t) = (2 cm) sin (8x - 16t) y (x, t) = (2 cm) sin (10 x - 20 t)

Explanation / Answer

1. 180 degrees

put t = 0 , and we get sin pi = 0 , so pi = 0 or 180

Now differentiate the equation and its slope is negative like k. cos pi = -negative vlaue

so pi is 180, if it is 0 then it is positive as it is 1

2. y ( x,t ) = 2 sin ( 4 x - 12t )

as everything else is in form of Y(x,t ) = 2 sin ( K (x -2t) )

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