11.5 ms at an angle 31 above horizontal. Assume the ball encounters no air resis

Question

11.5 ms at an angle 31 above horizontal. Assume the ball encounters no air resistance, and use a Cartesian coordinate system with the origin located at the ball's initial position. A 33% Part (a) create an expression for the footbal when caught by a receiver in terms of vo, 6, g, and h s horizontal velocity. Grade Summary Deductions 0% Potential 100% cos (a) cos(p) cos(e) 7 8 9 Submissions Attempts remaining: 3 sin(a) sin(p) sin(e) 4 5 6 per attempt) detailed view m t vo BACKSPACE CLEAR Hint feed Submit I give up! Hints: deduction per hint. Hints remaining 4 Feedback: deduction per feedback. A 33% Part b) The receiver catches the footba e same height as released by the quarterback. Create an expression for the time, te the football is in the air in terms of vo, e, g, and h A 33% Part (c) The receiver catches the ball at the same vertical height above the ground it was released. Calculate the horizontal distance, d in meters, between the receiver and the quarterback. All content 2017 Expert TA LLC

Explanation / Answer

part a)

for the final horizontal speed Vfx

final horizontal speed = initial horizontal speed

final horizontal speed = v0 * cos()

part b)

for the same height ,

time of football in air = 2 * vy/g

time of football in air = 2 * v0 * sin()/g

part c)

for the horizontal distance

horizontal distance = v0 * cos() * 2 * v0 * sin()/g

horizontal distance =11.5^2 * 2 * cos(31) * sin(31)/9.8

horizontal distance = 11.9 m

the horizontal distance is 11.9 m

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