11.19 A 3.00-m-long, 240-N, uniform rod at the zoo is held in a horizontal posit
ID: 1267000 • Letter: 1
Question
11.19 A 3.00-m-long, 240-N, uniform rod at the zoo is held in a horizontal position by two ropes at its ends (the figure (Figure 1) ). The left rope makes an angle of 150 deg with the rod and the right rope makes an angle with the horizontal. A 99-N howler monkey (Alouatta seniculus) hangs motionless 0.50 m from the right end of the rod as he carefully studies you.
A:
Calculate the tension in the left rope.
Express your answer using two significant figures.
B:
Calculate the tension in the right rope.
Express your answer using two significant figures.
C:
Calculate the angle ?.
Express your answer using two significant figures.
Explanation / Answer
tenstion in the left rope be T1
right rope be T2
T1cos(30) = T2cos(theta)
T1sin(30) + T2sin(theta) = 240+99
take moment balance equation about right end of the rod
99*.5+ 240*1.5 = T1sin(30)*3
tensiton in the left rope T1 = 273 N = 27 x 10^1
=> T2 = T1cos(30)/cos(theta)
T1(sin(30) + tan(theta)cos(30)) = 339
soving we get theta = 40.6 = 41 degrees
tension in the right rope T2 = 311.4 = 31 x 10^1
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