A tennis player swings her 1000 g racket with a speed of 10 m/s. She hits a 60 g

Question

A tennis player swings her 1000 g racket with a speed of 10 m/s. She hits a 60 g tennis ball that was approaching her at a speed of 23 m/s. The ball rebounds at 43 m/s.

(a) How fast is her racket moving immediately after the impact? You can ignore the interaction of the racket with her hand for the brief duration of the collision.
___ m/s

(b) If the tennis ball and racket are in contact for 10 ms, what is the average force that the racket exerts on the ball?
___ N

How does this compare to the gravitational force on the ball?
Favg / Wball = ___

Explanation / Answer

momentum is conserved

momentum before collision = momentum after collision

1000*(v - (-10 ) = 60 ( 43 - (-23))

v = -6.04 m/s

b) average force = dp/dt

= 0.06*(43+23) / 0.01

= 396 N

weigth of the ball = 0.06*9.8 = 0.588

Favg / Wball = 396 / 0.588 = 673.47

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